Project 2 - Optimization - Duplicate

priority = [ 2, 6, 1, 7, 10, 8, 5] time = [30,200,20,70,120,60, 150] # # define number of tasks: don't hardwire this but rather use the len() command n_tasks = len(priority) max_time = len(time) print ( f"TASK\tPRIORITY\tTIME TO COMPLETE") # you need to add an appropriate for loop here and modify the next print statement so that you can print out all tasks for i in range(len(priority)): print(f"{i+1}\t{priority[i]}\t\t{time[i]}")

test_list = [ 4, 5, 3, 7, 11, 2] max_value = max(test_list) # use function max() to find maximum value in list max_index = test_list.index(max_value) # use method list.index () to find the index where this max occurs print(f"The maximum value is {max_value} at index {max_index}") # print out results in formatted statement

test_list = [ 4, 5, 3, 7, 11, 2] time_list = [30, 45, 20, 120, 90, 70 ] max_value = max(test_list) max_index = test_list.index(max_value) task_time = time_list[max_index] # input the time it takes to complete this task print(f"The maximum value is priority {max_value} at index {max_index}.") print(f"The task time is {task_time} minutes.") # print out values as in Step #2 plus the time it takes to complete task

max_time = 6 * 60 # this is not the maximum time available for your example but rather for testing time_used = 3 * 60 # # Following 6 statements are from Step 3 test_list = [ 4, 5, 3, 7, 11, 2] time_list = [30, 45, 20, 120, 90, 70 ] max_value = max(test_list) max_index = test_list.index(max_value) task_time = time_list[max_index] print(f"The maximum value is priority {max_value} at index {max_index}.") print(f"The task time is {task_time} minutes.") # # Add conditional to see if this task can be completed in the allotted time if (time_used+task_time <= max_time): print(f"Current time used is {time_used}.") time_used += task_time print(f"After completing task {max_index+1}, time used is now {time_used}.") # if conditional is true, i.e., task can be completed update time_used # add print statements

# Input problem specific data and print it out from Step 1 priority = [ 2, 6, 1, 7, 10, 8, 5] time = [30,200,20,70,120,60, 150] n_tasks = len(priority) max_time = len(time) print (f"TASK\tPRIORITY\tTIME TO COMPLETE") for i in range(len(priority)): print(f"{i+1}\t{priority[i]}\t\t{time[i]}") # Initialize any variables before loop max_time = 6 * 60 time_used = 0 # add for loop to go through all tasks for tasks in range(n_tasks): # find highest priority left and task number it corresponds to from Step 3/4 max_value = max(priority) max_index = priority.index(max_value) task_time = time_list[max_index] # zero out this entry in the priority list so you won't find it again priority.pop(priority.index(max_value)) # add conditional to check to see if task can be completed as in Step 4 if (time_used+task_time <= max_time): print(f"Current time used is {time_used}.") time_used += task_time print(f"After completing task {max_index+1}, time used is now {time_used}.") else: print(f"There's not enough time for task {max_index+1}") # Print out the total time used for all tasks in day 1 print(f"The total time used on day 1 is {time_used}.")

# Input problem specific data and print it out from Step 1 priority = [ 2, 6, 1, 7, 10, 8, 5] time = [30,200,20,70,120,60, 150] n_tasks = len(priority) max_time = len(time) print (f"TASK\tPRIORITY\tTIME TO COMPLETE") for i in range(len(priority)): print(f"{i+1}\t{priority[i]}\t\t{time[i]}") # Initialize any variables before loop max_time = 6 * 60 time_used = 0 # add for loop to go through all tasks for tasks in range(n_tasks): # find highest priority left and task number it corresponds to from Step 3/4 max_value = max(priority) max_index = priority.index(max_value) task_time = time_list[max_index] # zero out this entry in the priority list so you won't find it again priority.pop(priority.index(max_value)) # add conditional to check to see if task can be completed as in Step 4 if (time_used+task_time < max_time): time_used += task_time print(f"After completing task {max_index+1}, time used is now {time_used}.") elif (time_used+task_time == max_time): # add conditional to check to see if task can be completed as in Step 4 # if this conditional is satisfied then add another conditional to check if time_used = max_time # if so break out of loop break else: print(f"There's not enough time for task {max_index+1}") # Print out the total time used for all tasks in day 1 print(f"The total time used on day 1 is {time_used}.")

# Input problem specific data old_priority = [ 2, 6, 1, 7, 10, 8, 5] time = [30,200,20,70,120,60, 150] n_tasks = len(old_priority) # # Create new priority list containing ratios # priority = [] # initialize the list which contains the new priorities which are original priority divided by # time it takes to complete this task # add for loop to create this list # # use method .append() to create elements of the new priority list # for i in range(n_tasks): priority.append(old_priority[i]/time[i]) print(f"{priority}") # Remainder of code should be the same; this is because we called the new list which contained the ratios the same as # before. max_time = len(time) print (f"TASK\tPRIORITY\tTIME TO COMPLETE") for i in range(len(priority)): print(f"{i+1}\t{priority[i]}\t\t{time[i]}") # Initialize any variables before loop max_time = 6 * 60 time_used = 0 # add for loop to go through all tasks for tasks in range(n_tasks): # find highest priority left and task number it corresponds to from Step 3/4 max_value = max(priority) max_index = priority.index(max_value) task_time = time_list[max_index] # zero out this entry in the priority list so you won't find it again priority.pop(priority.index(max_value)) # add conditional to check to see if task can be completed as in Step 4 if (time_used+task_time < max_time): time_used += task_time print(f"After completing task {max_index+1}, time used is now {time_used}.") elif (time_used+task_time == max_time): # add conditional to check to see if task can be completed as in Step 4 # if this conditional is satisfied then add another conditional to check if time_used = max_time # if so break out of loop break else: print(f"There's not enough time for task {max_index+1}") # Print out the total time used for all tasks in day 1 print(f"The total time used on day 1 is {time_used}.")