priority = [ 2, 6, 1, 7, 10, 8, 5] time = [30,200,20,70,120,60, 150] # # define number of tasks: don't hardwire this but rather use the len() command n_tasks = len (priority) max_time = 480 print ( f"TASK PRIORITY TIME TO COMPLETE") # you need to add an appropriate for loop here and modify the next print statement so that you can print out all tasks for k in range (n_tasks) : task = k + 1 print (f" {task} {priority[k]} {time[k]}")

test_list = [ 4, 5, 3, 7, 11, 2] max_value = max(test_list) # use function max() to find maximum value in list max_index = test_list.index(max_value) # use method list.index () to find the index where this max occurs print (f"the max value is {max_value} with an index of {max_index}") # print out results in formatted statement

test_list = [ 4, 5, 3, 7, 11, 2] time_list = [30, 45, 20, 120, 90, 70 ] max_value = max(test_list) max_index = test_list.index(max_value) task_time = time_list[max_index] # input the time it takes to complete this task print (f"the max value is {max_value} with an index of {max_index} and time of {task_time} minutes") # print out values as in Step #2 plus the time it takes to complete task

max_time = 6 * 60 # this is not the maximum time available for your example but rather for testing time_used = 3 * 60 # # Following 6 statements are from Step 3 test_list = [ 4, 5, 3, 7, 11, 2] time_list = [30, 45, 20, 120, 90, 70 ] max_value = max(test_list) max_index = test_list.index(max_value) task_time = time_list[max_index] task = max_index + 1 print # # Add conditional to see if this task can be completed in the allotted time if ( time_used + task_time <= max_time ) : time_used = task_time + time_used print (f"Task {task} was added and total time used is {time_used}") # if conditional is true, i.e., task can be completed update time_used # add print statements

# Input problem specific data and print it out from Step 1 priority = [ 2, 6, 1, 7, 10, 8, 5] time = [30,200,20,70,120,60, 150] n_tasks = len(priority) max_time = 480 print ( f"TASK PRIORITY TIME TO COMPLETE") # # Initialize any variables before loop time_used = 0 # # add for loop to go through all tasks # for k in range (n_tasks) : max_value = max(priority) max_index = priority.index(max_value) task_time = time[max_index] task_number = max_index + 1 priority.pop(max_index) time.pop(max_index) if (time_used + task_time <= max_time) : time_used = time_used + task_time print (f" {task_number} {max_value} {time_used}") print (f"The total time used for all tasks is {time_used} minutes") # # find highest priority left and task number it corresponds to from Step 3/4 # # zero out this entry in the priority list so you won't find it again # # add conditional to check to see if task can be completed as in Step 4 # # Print out the total time used for all tasks in day 1

# Input problem specific data and print it out from Step 1 priority = [ 2, 6, 1, 7, 10, 8, 5] time = [30,200,20,70,120,60, 150] n_tasks = len (priority) max_time = 480 print ( f"TASK PRIORITY TIME TO COMPLETE") # # Initialize any variables before loop time_used = 0 # # add for loop to go through all tasks # for k in range (n_tasks) : max_value = max(priority) max_index = priority.index(max_value) task_time = time[max_index] task_number = max_index + 1 priority.pop(max_index) time.pop(max_index) if (time_used + task_time <= max_time) : time_used = time_used + task_time print (f" {task_number} {max_value} {time_used}") if (time_used == max_time) : break print (f"The total time used for all tasks is {time_used} minutes") # # find highest priority left and task number it corresponds to from Step 3/4 # # zero out this entry in the priority list so you won't find it again # # add conditional to check to see if task can be completed as in Step 4 # if this conditional is satisfied then add another conditional to check if time_used = max_time; if so break out of loop # # Print out the total time used for all tasks in day 1

# Input problem specific data old_priority = [ 2, 6, 1, 7, 10, 8, 5] time = [30,200,20,70,120,60, 150] # n_tasks = # # Create new priority list containing ratios # priority = [] # initialize the list which contains the new priorities which are original priority divided by # time it takes to complete this task # add for loop to create this list # use method .append() to create elements of the new priority list # # Remainder of code should be the same; this is because we called the new list which contained the ratios the same as # before.