#John Bible 11/28/21 #What I learned was how to use containment, operator precedence, and identity. #What I had problems with was nothing I got through this without any issues.

lst_container = [4, 8, 5, 6] x = 5 if (x in lst_container): print(x, "is contained in list") else: print(x, "is NOT contained in list") x = 10 if (x in lst_container): print(x, "is contained in list") else: print(x, "is NOT contained in list")

lst_container = [4, [7, 3], 'string element'] # 4 is an element in lst_container x = 4 print(x, "contained in lst_container:", x in lst_container) # 7 is an element of a list inside lst_container, but it is NOT an element of the lst_container x = 7 print(x, "contained in lst_container:", x in lst_container) # [7, 3] is an element of lst_container x = [7, 3] print(x, "contained in lst_container:", x in lst_container)

sentence = "This is a test sentence" word1 = "test" word2 = "something" # testing if word1 is a substring of sentence if (word1 in sentence): print(word1, "is contained in:", sentence) else: print(word1, "is not contained in:", sentence) # testing if word2 is a substring of sentence if (word2 in sentence): print(word2, "is contained in:", sentence) else: print(word2, "is not contained in:", sentence) # another method to test if word2 is a substring of sentence # using the not operator if (word2 not in sentence): print(word2, "is not contained in:", sentence) else: print(word2, "is contained in:", sentence)

# [ ] Write a program to prompt the user for an integer input between 0 and 100 # then print if the number is contained in `lst` #This will prompt the user for an integer input between 0 and 100 and then print if the number is in lst lst = [22, 89, 69, 78, 58, 22, 56, 13, 74, 8, 32, 58, 8, 63, 46, 79, 9, 38, 25, 96] x=input("Enter a number between 0 and 100:") x=int(x) if (x in lst): print(x, "is contained in list") else: print(x, "is NOT contained in list")

# [ ] The `records` list contains information about a company's employees # each of the elements in `records` is a list containing the name and ID of an employee. # Write a program to test if `applicant` is contained in `records` and display an appropriate message #This will test if applicant is contained in records and display an appropriate message # Records of names and IDs records = [['Colette', 22347], ['Skye', 35803], ['Alton', 45825], ['Jin', 24213]] applicant = ['Joana', 20294] if (applicant in records): print(applicant, "is in our records") else: print(applicant, "is NOT in our records")

# [ ] Write a program to prompt the user for a letter (capital or small) then print if the letter is a vowel # HINT: Use a string containing all the vowels and the `in` or `not in` operator #This will prompt the user for a letter then print if the letter is a vowel lst=["A","E","I","O","U","Y"] x=input("Enter a letter") x=x.upper() if (x in lst): print(x, "is a vowel") else: print(x, "is NOT a vowel")

# x, y: equal, identical x = 5 y = 5 print("x equal y ? ", x == y) print("x is identical to y ?", x is y)

# x, y: not equal, not identical x = 5 y = 6 print("x equal y ? ", x == y) print("x is identical to y ?", x is y)

# x, y: equal, not identical x = 5.6 y = 5.6 print("x equal y ? ", x == y) print("x is identical to y ?", x is y)

# x, y: not equal, not identical x = 5.6 y = 10.6 print("x equal y ? ", x == y) print("x is identical to y ?", x is y)

# Different lists containing the same data x = [4, 9, 8] y = [4, 9, 8] # x and y are equal, because they contain the same data # x and y are NOT identical, because they are saved in different memory locations print("x equal y ? ", x == y) print("x is identical to y ?", x is y) # Because they are not identical, changing x does not affect y x[1] = 5 print() print("After changing x[1]") print("x =", x) print("y =", y) print("x equal y ? ", x == y) print("x is identical to y ?", x is y)

# Identical list x = [4, 9, 8] y = x # x and y are equal, because they contain the same data # x and y are identical, because they are saved in the same memory location print("x equal y ? ", x == y) print("x is identical to y ?", x is y) # Because they are identical, changing x also changes y x[1] = 5 print() print("After changing x[1]") print("x =", x) print("y =", y) print("x equal y ? ", x == y) print("x is identical to y ?", x is y)

# s1, s2: equal, not identical s1 = 'whole milk' s2 = 'whole milk' print("s1 equal s2 ? ", s1 == s2) print("s1 is identical to s2 ?", s1 is s2) print("s1 is not identical to s2 ?", s1 is not s2)

# s1, s2: equal, identical s1 = 'whole milk' s2 = s1 print("s1 equal s2 ? ", s1 == s2) print("s1 is identical to s2 ?", s1 is s2) print("s1 is not identical to s2 ?", s1 is not s2)

# s1, s2: equal, identical (after interpreter optimization) s1 = 'python' s2 = 'python' print("s1 equal s2 ? ", s1 == s2) print("s1 is identical to s2 ?", s1 is s2) print("s1 is not identical to s2 ?", s1 is not s2)

# s1, s2: not equal, not identical s1 = 'python' s2 = 'java' print("s1 equal s2 ? ", s1 == s2) print("s1 is identical to s2 ?", s1 is s2) print("s1 is not identical to s2 ?", s1 is not s2)

# [ ] Write a program to: # 1) Create a variable `e` that is equal but NOT identical to `s` # 2) Test the equality and identity of `s` and `e` and print the results # 3) Create a variable `i` that is equal and identical to `s` # 4) Test the equality and identity of `s` and `i` and print the results # 5) Test the equality and identity of `e` and `i` and print the results #This will create variable e that is equal but not identical to s, test the equality and identity of s and e and print the results, create a variable i that is equal and identical to s, test the equality and identity of s and i and print the results, test the equality and identity of e and i and print the results s = "Whole Wheat Bread" #TODO e= "Whole Wheat Bread" print("e equal s ? ", e == s) print("e is identical to s ?", e is s) i=s print("s equal i ? ", s == i) print("s is identical to i ?", s is i) print("e equal i ? ", e == i) print("e is identical to i ?", e is i)

# [ ] Write a program to: # 1) Create a variable `e` that is equal but NOT identical to `x` # 2) Test the equality and identity of `x` and `e` and print the results # 3) Create a variable `i` that is equal and identical to `x` # 4) Test the equality and identity of `x` and `i` and print the results # 5) Test the equality and identity of `e` and `i` and print the results #This will create variable e which will be equal but not identical to x, test equality and indentity of x and e then printing the results, create i which will be equal and identical to x, test the equality and identity of x and i and print the results, test the equality and identity of e and i and print the results x = [[-1, 2],[3, 4],[-5, 6]] #TODO e= [[-1, 2],[3, 4],[-5, 6]] print("e equal x ? ", e == x) print("e is identical to x ?", e is x) i=x print("x equal i ? ", x == i) print("x is identical to i ?", x is i) print("e equal i ? ", e == i) print("e is identical to i ?", e is i)

# * has higher precedence 2 + 3 * 6

# To change precedence, we add ( ) (2 + 3) * 6

# Arithmetic and relational operations 3 * 2 < 10

# Exponentiation has a higher precedence 2**3 + 1 == 16

# Adding () changes the precedence of 3 + 1 and the exponentiation operator 2 ** (3 + 1) == 16

# Arithmetic, relational, and Boolean operators 2 ** (3 + 1) == 16 and 3 * 2 < 10

# Arithmetic, relational, Boolean, and containment operators 2 ** (3 + 1) != 16 or 3 * 2 in [5, 6, 3]

# Unexpected outcome! 6 < 10 != True

# Unexpected outcome! 6 < 10 != False

# Expected outcome after adding () (6 < 10) != True

# [ ] Correct the following expression so the answer is `True` #This will make the answer True (6 + 2 < 9) == True

# [ ] Correct the following expression so the answer is `True` #This will make the answer True 3 ** (2 + 1) >= 3 * 8 + 1

# [ ] Correct the following expression so the answer is `True` #This will make the answer True (5 + 3) * 2 == 16

# [ ] Correct the following expression so the answer is `True` #This will make the answer True (4 > 3 and 5 + 6 > 7) == True