#John Bible 12/9/21 #What I learned is dictionary basics, how to loop with dictionary items, and dictionary operations #What I had trouble with was task 2 part 2 bu I overcame this by doing something simialr to what was asked.

# Create a dictionary of contacts; names as keys, phone numbers as values contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"} # Ask user for a name, then display the number name = input("Enter a name: ") # If name is not in the contacts dictionary, a KeyError exception will be raised number = contacts[name] print("Number is: {:s}".format(number))

# Create a dictionary of contacts; names as keys, phone numbers as values contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"} # Ask user for a name, then display the number name = input("Enter a name: ") # If name is not in the contacts dictionary, the exception message will be displayed try: number = contacts[name] print("Number is: {:s}".format(number)) except KeyError as exception_object: print("{:s} was not found in contacts".format(name))

# Create a dictionary of contacts; names as keys, phone numbers as values contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"} # Ask user for a name and number name = input("Enter a name: ") number = input("Enter a number: ") # If the name exists in the dictionary, the number will be updated # If the name does NOT exist in the dictionary, a new name:number pair will be added contacts[name] = number print("Updated contact:", contacts)

# Create a dictionary of contacts; names as keys, phone numbers as values contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"} # Ask user for a name and number name = input("Enter a name: ") # If the name is not in the contacts dictionary, display the exception message try: number = contacts.pop(name) print("{:s}: {:s} was deleted from contacts".format(name, number)) except KeyError as exception_object: print("{:s} was not found in contacts".format(name)) print("Updated contact:", contacts)

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} # Display the price for the item name item = 'Bread' print("{} price = {:.2f}".format(item, groceries[item])) # Add a new key:value pair to the dictionary groceries['Banana']= 1.00 print('Adding Banana:') print(groceries) # Modify a dictionary element groceries['Banana'] = 1.10 print('Modifying Banana:') print(groceries) # Remove a dictionary element print("Removing: '{}':{:.2f}".format('Banana', groceries.pop('Banana'))) print(groceries)

# [ ] The `data` list contains information about a company's employees. # Use the `data` list and an appropriate loop to create a dictionary of employees. # Use IDs (as keys) and names (as values). # Ignore the email addresses for now. # The created dictionary should look like: # {57394: 'Suresh Datta', 48539: 'Colette Browning', 58302: 'Skye Homsi', 48502: 'Hiroto Yamaguchi', 48291: 'Tobias Ledford', 48293: 'Jin Xu', 23945: 'Joana Dias', 85823: 'Alton Derosa'} #This will create a dictionary of employees data = [["Suresh Datta", 57394, "suresh@example.com"], ["Colette Browning", 48539, "colette@example.com"], ["Skye Homsi", 58302, "skye@example.com"], ["Hiroto Yamaguchi", 48502, "hiroto@example.com"], ["Tobias Ledford", 48291, "tobias@example.com", "Tamara Babic", 58201, "tamara@example.com"], ["Jin Xu", 48293, "jin@example.com"], ["Joana Dias", 23945, "joana@example.com"], ["Alton Derosa", 85823, "alton@example.com"]] for key in data: print(key[1],":",key[0])

# [ ] Use the `records` dictionary in a program that 1. asks the user for an ID and 2. prints the name of the associated employee. # Display an appropriate message if the ID is not found in the dictionary. #This will 1. asks the user for an ID and 2. prints the name of the associated employee 3.Display an appropriate message if the ID is not found records = {57394: 'Suresh Datta', 48539: 'Colette Browning', 58302: 'Skye Homsi', 48502: 'Hiroto Yamaguchi', 48291: 'Tobias Ledford', 48293: 'Jin Xu', 23945: 'Joana Dias', 85823: 'Alton Derosa'} # Ask user for an ID, then display the name UID=input("Enter an ID:") # If the ID is not in the dictionary, display the exception message try: search=records[int(UID)] print(search) if UID in records: print("No employee found") except KeyError as exception_object: print("No employee found")

# [ ] Use the `records` dictionary in a program to 1. ask the user for an ID then 2. delete the employee record associated with the ID # The program should display an appropriate message if the ID is not found in the dictionary. # hint: Try/Catch may be helpful here #This will 1. ask the user for an ID then 2. delete the employee record associated with the ID 3.Display an appropriate message if the ID is not found records = {57394: 'Suresh Datta', 48539: 'Colette Browning', 58302: 'Skye Homsi', 48502: 'Hiroto Yamaguchi', 48291: 'Tobias Ledford', 48293: 'Jin Xu', 23945: 'Joana Dias', 85823: 'Alton Derosa'} # ask user for an ID UID=input("Enter an ID:") # if ID is not in the dictionary, the exception message will be displayed try: search=records[int(UID)] print(search) records.pop(search) if search not in records: print("No employee found") except KeyError as exception_object: print("No employee found")

D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'} # Iterate over the keys of D for key in D.keys(): print("D[{}] = '{}'".format(key, D[key]))

D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'} # Iterate over the sorted keys of D # Keys sorted alphabetically because they are all strings for key in sorted(D.keys()): print("D[{}] = '{}'".format(key, D[key]))

D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'} for value in D.values(): print(value)

D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'} for (key, value) in D.items(): print(key,':', value)

D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'} for key, value in D.items(): print(key,':', value)

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} # Display the price for the items in a sorted order for item in sorted(groceries.keys()): print("{} = {:.2f}".format(item, groceries[item]))

# [ ] The `data` list contains information about a company's employees # Use the `data` list and an appropriate loop to create a dictionary of # IDs (as keys): [name, email] (as values) # The resulting dictionary should look like: # {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']} #This will create a dictionary of IDs (as keys): [name, email] (as values) data = [["Suresh Datta", 57394, "suresh@example.com"], ["Colette Browning", 48539, "colette@example.com"], ["Skye Homsi", 58302, "skye@example.com"], ["Hiroto Yamaguchi", 48502, "hiroto@example.com"], ["Tobias Ledford", 48291, "tobias@example.com", "Tamara Babic", 58201, "tamara@example.com"], ["Jin Xu", 48293, "jin@example.com"], ["Joana Dias", 23945, "joana@example.com"], ["Alton Derosa", 85823, "alton@example.com"]] for key in data: print(key[1],":",[key[0],key[2]])

# [ ] Write a program to display the content of the `records` dictionary as shown here # Make sure to display the header the dictionary makes sense to the viewer # Note the IDs are sorted in an ascending order #This will display the content of the records dictionary similar to as shown here ''' Name | ID | Email ________________________________________________________ Joana Dias | 23945 | joana@example.com Tobias Ledford | 48291 | tobias@example.com Jin Xu | 48293 | jin@example.com Hiroto Yamaguchi | 48502 | hiroto@example.com Colette Browning | 48539 | colette@example.com Suresh Datta | 57394 | suresh@example.com Skye Homsi | 58302 | skye@example.com Alton Derosa | 85823 | alton@example.com ''' records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']} # Display the header print(" ID"," Name"," Email") # Display the data (sorted by ID) for key in sorted(records.keys()): print("{} = '{}'".format(key,records[key]))

# [ ] The company's domain has changed from (example.com) to (example.org) # Write a program to modify the email addresses in the `records` dictionary to reflect this change #This will modify the email addresses in the `records` dictionary to reflect this change records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']} records = {57394: ['Suresh Datta', 'suresh@example.org'], 48539: ['Colette Browning', 'colette@example.org'], 58302: ['Skye Homsi', 'skye@example.org'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.org'], 48291: ['Tobias Ledford', 'tobias@example.org'], 48293: ['Jin Xu', 'jin@example.org'], 23945: ['Joana Dias', 'joana@example.org'], 85823: ['Alton Derosa', 'alton@example.org']} # Display the updated dictionary print(records) # Display the header print(" ID"," Name"," Email") # Display the data (sorted by ID) for key in sorted(records.keys()): print("{} = '{}'".format(key,records[key]))

# [ ] You want to send a mass email to all company employees, so you need a list of all the email addresses in `records` # Write a program to extract the email addresses from the `records` dictionary and store them in a list # The output list should look like: # ['suresh@example.com', 'colette@example.com', 'skye@example.com', 'hiroto@example.com', 'tobias@example.com', 'jin@example.com', 'joana@example.com', 'alton@example.com'] # Hint: use the `.values()` method #This will extract the email addresses from the `records` dictionary and store them in a list records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']} l=[] for key in records: l.append(records[key].pop()) print(l)

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} item = input("Please enter an item name: ") # Using .keys() if (item in groceries.keys()): print("Price of {} is: ${:4.2f}".format(item, groceries[item])) elif (item not in groceries): print("Price not in the dictionary")

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} item = input("Please enter a item: ") # Without using .keys() if (item in groceries): print("Price of {} is: ${:4.2f}".format(item, groceries[item])) elif (item not in groceries): print("Price not in the dictionary")

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} price = float(input("Please enter an exact price: ")) if (price in groceries.values()): print("There is a matching grocery") else: print("There are no groceries matching this price")

# Create 2 equal but not identical dictionaries D1 = {0:'number 0', 1:'number 1', 2:'number 2'} D2 = {1:'number 1', 0:'number 0', 2:'number 2'} print("Equality: D1 == D2 ?", D1 == D2) print("Identity: D1 is D2 ?", D1 is D2)

# Create 2 equal and identical dictionaries D1 = {0:'number 0', 1:'number 1', 2:'number 2'} D2 = D1 D1[0] = 'changed number' print("Equality: D1 == D2 ?", D1 == D2) print("Identity: D1 is D2 ?", D1 is D2) print("D2 after changing D1:", D2)

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} # The length of a dictionary = how many key:value pairs it has print("{} groceries total".format(len(groceries)))

# Write a program that can ONLY update the PRICE of an existing grocery item in the `groceries` dictionary. # The item and updated price should be entered by the user. # If the user enters a new item, the program should NOT create a new dictionary item. # It should instead display an error message. #This will only update the price of an existing grocery item in the groceries dictionary groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} item=input("Enter the name of your item:") price=input("Enter a price:") item=item.title() if item not in groceries: print("Item not found") else: groceries[item]=price print(groceries)

# [ ] Write a program to find out the number of employees stored in `records`. #This will find out the number of employees stored in records records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']} count=0 for key in records: count+=1 print(count)