# Pavan Kumpatla
# December 24, 2021.
# I learned how to create, access, delete, change, add, sort and more with dictionaries
# I had trouble in task 2
# Create a dictionary of contacts; names as keys, phone numbers as values
contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"}
# dict
# Ask user for a name, then display the number
name = input("Enter a name: ")
# stores user input
# If name is not in the contacts dictionary, a KeyError exception will be raised
number = contacts[name]
# stores the value of the key from contacts
print("Number is: {:s}".format(number))
# prints, formats
# Create a dictionary of contacts; names as keys, phone numbers as values
contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"}
# dict
# Ask user for a name, then display the number
name = input("Enter a name: ")
# stores user input
# If name is not in the contacts dictionary, the exception message will be displayed
try:
# try
number = contacts[name]
# stores the value of the key from contacts
print("Number is: {:s}".format(number))
# prints, formats
except KeyError as exception_object:
# except error
print("{:s} was not found in contacts".format(name))
# prints this instead of error
# Create a dictionary of contacts; names as keys, phone numbers as values
contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"}
# dict
# Ask user for a name and number
name = input("Enter a name: ")
# stores user input
number = input("Enter a number: ")
# stores user input
# If the name exists in the dictionary, the number will be updated
# If the name does NOT exist in the dictionary, a new name:number pair will be added
contacts[name] = number
# updates the value of key to number
print("Updated contact:", contacts)
# prints
# Create a dictionary of contacts; names as keys, phone numbers as values
contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"}
# dict
# Ask user for a name and number
name = input("Enter a name: ")
# stores user input
# If the name is not in the contacts dictionary, display the exception message
try:
number = contacts.pop(name)
# stores the value of the key that is getting popped
print("{:s}: {:s} was deleted from contacts".format(name, number))
# prints, formats
except KeyError as exception_object:
# excepts error
print("{:s} was not found in contacts".format(name))
# prints this instead
print("Updated contact:", contacts)
# prints
# Create a dictionary of grocery items and associated prices
groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59}
# dict
# Display the price for the item name
item = 'Bread'
# stores
print("{} price = {:.2f}".format(item, groceries[item]))
# prints, formats
# Add a new key:value pair to the dictionary
groceries['Banana']= 1.00
# replaces value of key
print('Adding Banana:')
# prints
print(groceries)
# prints
# Modify a dictionary element
groceries['Banana'] = 1.10
# replaces value of key
print('Modifying Banana:')
# prints
print(groceries)
# prints
# Remove a dictionary element
print("Removing: '{}':{:.2f}".format('Banana', groceries.pop('Banana')))
# prints, formats, pops
print(groceries)
# prints
# [ ] The `data` list contains information about a company's employees.
# Use the `data` list and an appropriate loop to create a dictionary of employees.
# Use IDs (as keys) and names (as values).
# Ignore the email addresses for now.
# The created dictionary should look like:
# {57394: 'Suresh Datta', 48539: 'Colette Browning', 58302: 'Skye Homsi', 48502: 'Hiroto Yamaguchi', 48291: 'Tobias Ledford', 48293: 'Jin Xu', 23945: 'Joana Dias', 85823: 'Alton Derosa'}
data = [["Suresh Datta", 57394, "suresh@example.com"], ["Colette Browning", 48539, "colette@example.com"], ["Skye Homsi", 58302, "skye@example.com"], ["Hiroto Yamaguchi", 48502, "hiroto@example.com"], ["Tobias Ledford", 48291, "tobias@example.com", "Tamara Babic", 58201, "tamara@example.com"], ["Jin Xu", 48293, "jin@example.com"], ["Joana Dias", 23945, "joana@example.com"], ["Alton Derosa", 85823, "alton@example.com"]]
# list
data1 = {}
# dict
for item in data:
# for item in data
data1[item[1]] = item[0]
# index 1 of item equals to index 0 of item (to dict form)
print(data1)
# prints
# [ ] Use the `records` dictionary in a program that 1. asks the user for an ID and 2. prints the name of the associated employee.
# Display an appropriate message if the ID is not found in the dictionary.
records = {57394: 'Suresh Datta', 48539: 'Colette Browning', 58302: 'Skye Homsi', 48502: 'Hiroto Yamaguchi', 48291: 'Tobias Ledford', 48293: 'Jin Xu', 23945: 'Joana Dias', 85823: 'Alton Derosa'}
# dict
# Ask user for an ID, then display the name
# If the ID is not in the dictionary, display the exception message
try:
# try
user = int(input("Type in the Id:- "))
# stores user input in int form
if user in records.keys():
# if user in the keys of records
print("Employee Name:-", records[user])
# print this
else:
# else
print("Key not found")
# print this
except Exception as exception_object:
# except unexpected errors
print(exception_object)
# prints this instead
except KeyError as exception_object:
# excepts error
print("Invalid Key")
# prints this instead
# [ ] Use the `records` dictionary in a program to 1. ask the user for an ID then 2. delete the employee record associated with the ID
# The program should display an appropriate message if the ID is not found in the dictionary.
# hint: Try/Catch may be helpful here
records = {57394: 'Suresh Datta', 48539: 'Colette Browning', 58302: 'Skye Homsi', 48502: 'Hiroto Yamaguchi', 48291: 'Tobias Ledford', 48293: 'Jin Xu', 23945: 'Joana Dias', 85823: 'Alton Derosa'}
# ask user for an ID
# if ID is not in the dictionary, the exception message will be displayed
try:
# try
user = int(input("Type in the Id:- "))
# stores user input in int form
if user in records.keys():
# if user in the keys of records
print("Deleted Employee's Name:-", records[user])
# print this
records.pop(user)
print(records)
else:
# else
print("Key not found")
# print this
except Exception as exception_object:
# except unexpected errors
print(exception_object)
# prints this instead
except KeyError as exception_object:
# excepts error
print("Invalid Key")
# prints this instead
D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'}
# dict
# Iterate over the keys of D
for key in D.keys():
# for all the keys in D
print("D[{}] = '{}'".format(key, D[key]))
# prints, formats
D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'}
# dict
# Iterate over the sorted keys of D
# Keys sorted alphabetically because they are all strings
for key in sorted(D.keys()):
# for every key in D, which is sorted
print("D[{}] = '{}'".format(key, D[key]))
# prints, formats
D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'}
# dict
for value in D.values():
# for every value in D
print(value)
# prints
D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'}
# dict
for (key, value) in D.items():
# for every item in D
print(key,':', value)
# prints
D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'}
# dict
for key, value in D.items():
# for items in D
print(key,':', value)
# prints
# Create a dictionary of grocery items and associated prices
groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59}
# Display the price for the items in a sorted order
for item in sorted(groceries.keys()):
# for every key in groceries, which is sorted
print("{} = {:.2f}".format(item, groceries[item]))
# prints, formats
# [ ] The `data` list contains information about a company's employees
# Use the `data` list and an appropriate loop to create a dictionary of
# IDs (as keys): [name, email] (as values)
# The resulting dictionary should look like:
# {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']}
data = [["Suresh Datta", 57394, "suresh@example.com"], ["Colette Browning", 48539, "colette@example.com"], ["Skye Homsi", 58302, "skye@example.com"], ["Hiroto Yamaguchi", 48502, "hiroto@example.com"], ["Tobias Ledford", 48291, "tobias@example.com", "Tamara Babic", 58201, "tamara@example.com"], ["Jin Xu", 48293, "jin@example.com"], ["Joana Dias", 23945, "joana@example.com"], ["Alton Derosa", 85823, "alton@example.com"]]
# list
for item in data:
# for item in data
print("{", item[1], ": [", item[0], ",", item[2], "]}")
# prints
# I have absolutely no idea how to do this. I tried my best
# [ ] Write a program to display the content of the `records` dictionary as shown here
# Make sure to display the header the dictionary makes sense to the viewer
# Note the IDs are sorted in an ascending order
'''
Name | ID | Email
________________________________________________________
Joana Dias | 23945 | joana@example.com
Tobias Ledford | 48291 | tobias@example.com
Jin Xu | 48293 | jin@example.com
Hiroto Yamaguchi | 48502 | hiroto@example.com
Colette Browning | 48539 | colette@example.com
Suresh Datta | 57394 | suresh@example.com
Skye Homsi | 58302 | skye@example.com
Alton Derosa | 85823 | alton@example.com
'''
records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']}
# dict
# Display the header
print("| Name | ID | Email |")
# prints
for key, value in sorted(records.items()):
# for items in the sorted dict
print(" {} {} {}".format(value[0], key, value[1]))
# prints, formats
# I tried
# [ ] The company's domain has changed from (example.com) to (example.org)
# Write a program to modify the email addresses in the `records` dictionary to reflect this change
records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']}
# dict
# Display the updated dictionary
# Display the header
# Display the data (sorted by ID)
address1 = "org"
# stores
address2 = "com"
# stores
records[address2] = address1
# replaces
print(records)
# prints
# I genuinely have no idea why this is not working. I had to refer to the
# notes section. Even then, it's not working.
# [ ] You want to send a mass email to all company employees, so you need a list of all the email addresses in `records`
# Write a program to extract the email addresses from the `records` dictionary and store them in a list
# The output list should look like:
# ['suresh@example.com', 'colette@example.com', 'skye@example.com', 'hiroto@example.com', 'tobias@example.com', 'jin@example.com', 'joana@example.com', 'alton@example.com']
# Hint: use the `.values()` method
records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']}
# dict
for email in records.values():
# for email in the values of records
print("['" + email[1] + "'], ", end = " ")
# prints
# I failed to do the shell ( "[]" ).
# Create a dictionary of grocery items and associated prices
groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59}
# dict
item = input("Please enter an item name: ")
# stores user input
# Using .keys()
if (item in groceries.keys()):
# if item is in the keys of groceries
print("Price of {} is: ${:4.2f}".format(item, groceries[item]))
# prints, formats
elif (item not in groceries):
# else if the item is not in groceries
print("Price not in the dictionary")
# prints
# Create a dictionary of grocery items and associated prices
groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59}
# dict
item = input("Please enter a item: ")
# stores user input
# Without using .keys()
if (item in groceries):
# if item is in groceries
print("Price of {} is: ${:4.2f}".format(item, groceries[item]))
# prints, formats
elif (item not in groceries):
# else if item is not in groceries
print("Price not in the dictionary")
# prints
# Create a dictionary of grocery items and associated prices
groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59}
# dict
price = float(input("Please enter an exact price: "))
# stores in float form
if (price in groceries.values()):
# if price is in the values of groceries
print("There is a matching grocery")
# prints
else:
# else
print("There are no groceries matching this price")
# prints
# Create 2 equal but not identical dictionaries
D1 = {0:'number 0', 1:'number 1', 2:'number 2'}
D2 = {1:'number 1', 0:'number 0', 2:'number 2'}
# dict
print("Equality: D1 == D2 ?", D1 == D2)
# D1 equals D2 = Yes
print("Identity: D1 is D2 ?", D1 is D2)
# D1 is D2 = No
# Create 2 equal and identical dictionaries
D1 = {0:'number 0', 1:'number 1', 2:'number 2'}
# dict
D2 = D1
# D1 is now D2
D1[0] = 'changed number'
# replaces index 0 of D1
print("Equality: D1 == D2 ?", D1 == D2)
# D1 equals D2 = Yes
print("Identity: D1 is D2 ?", D1 is D2)
# D1 is D2 = No
print("D2 after changing D1:", D2)
# prints
# Create a dictionary of grocery items and associated prices
groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59}
# dict
# The length of a dictionary = how many key:value pairs it has
print("{} groceries total".format(len(groceries)))
# prints, formats
# Write a program that can ONLY update the PRICE of an existing grocery item in the `groceries` dictionary.
# The item and updated price should be entered by the user.
# If the user enters a new item, the program should NOT create a new dictionary item.
# It should instead display an error message.
groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59}
# dict
item = input("Type In The Item:- ")
# stores user input
price = float(input("Type In The Price:- "))
# stores user input in float form
if item not in groceries:
# if item is not in groceries
print("Error: Item Not Found")
# print this
else:
# else
groceries[item] = price
# the item (key) in groceries will not equal to the price (value)
print(groceries)
# print this
# [ ] Write a program to find out the number of employees stored in `records`.
records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']}
# dict
print(len(records))
# prints length of records