# Pavan Kumpatla # December 24, 2021. # I learned how to create, access, delete, change, add, sort and more with dictionaries # I had trouble in task 2

# Create a dictionary of contacts; names as keys, phone numbers as values contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"} # dict # Ask user for a name, then display the number name = input("Enter a name: ") # stores user input # If name is not in the contacts dictionary, a KeyError exception will be raised number = contacts[name] # stores the value of the key from contacts print("Number is: {:s}".format(number)) # prints, formats

# Create a dictionary of contacts; names as keys, phone numbers as values contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"} # dict # Ask user for a name, then display the number name = input("Enter a name: ") # stores user input # If name is not in the contacts dictionary, the exception message will be displayed try: # try number = contacts[name] # stores the value of the key from contacts print("Number is: {:s}".format(number)) # prints, formats except KeyError as exception_object: # except error print("{:s} was not found in contacts".format(name)) # prints this instead of error

# Create a dictionary of contacts; names as keys, phone numbers as values contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"} # dict # Ask user for a name and number name = input("Enter a name: ") # stores user input number = input("Enter a number: ") # stores user input # If the name exists in the dictionary, the number will be updated # If the name does NOT exist in the dictionary, a new name:number pair will be added contacts[name] = number # updates the value of key to number print("Updated contact:", contacts) # prints

# Create a dictionary of contacts; names as keys, phone numbers as values contacts = {"Suresh Datta": "345-555-0101", "Colette Browning": "483-555-0119", "Skey Homsi": "485-555-0195"} # dict # Ask user for a name and number name = input("Enter a name: ") # stores user input # If the name is not in the contacts dictionary, display the exception message try: number = contacts.pop(name) # stores the value of the key that is getting popped print("{:s}: {:s} was deleted from contacts".format(name, number)) # prints, formats except KeyError as exception_object: # excepts error print("{:s} was not found in contacts".format(name)) # prints this instead print("Updated contact:", contacts) # prints

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} # dict # Display the price for the item name item = 'Bread' # stores print("{} price = {:.2f}".format(item, groceries[item])) # prints, formats # Add a new key:value pair to the dictionary groceries['Banana']= 1.00 # replaces value of key print('Adding Banana:') # prints print(groceries) # prints # Modify a dictionary element groceries['Banana'] = 1.10 # replaces value of key print('Modifying Banana:') # prints print(groceries) # prints # Remove a dictionary element print("Removing: '{}':{:.2f}".format('Banana', groceries.pop('Banana'))) # prints, formats, pops print(groceries) # prints

# [ ] The `data` list contains information about a company's employees. # Use the `data` list and an appropriate loop to create a dictionary of employees. # Use IDs (as keys) and names (as values). # Ignore the email addresses for now. # The created dictionary should look like: # {57394: 'Suresh Datta', 48539: 'Colette Browning', 58302: 'Skye Homsi', 48502: 'Hiroto Yamaguchi', 48291: 'Tobias Ledford', 48293: 'Jin Xu', 23945: 'Joana Dias', 85823: 'Alton Derosa'} data = [["Suresh Datta", 57394, "suresh@example.com"], ["Colette Browning", 48539, "colette@example.com"], ["Skye Homsi", 58302, "skye@example.com"], ["Hiroto Yamaguchi", 48502, "hiroto@example.com"], ["Tobias Ledford", 48291, "tobias@example.com", "Tamara Babic", 58201, "tamara@example.com"], ["Jin Xu", 48293, "jin@example.com"], ["Joana Dias", 23945, "joana@example.com"], ["Alton Derosa", 85823, "alton@example.com"]] # list data1 = {} # dict for item in data: # for item in data data1[item[1]] = item[0] # index 1 of item equals to index 0 of item (to dict form) print(data1) # prints

# [ ] Use the `records` dictionary in a program that 1. asks the user for an ID and 2. prints the name of the associated employee. # Display an appropriate message if the ID is not found in the dictionary. records = {57394: 'Suresh Datta', 48539: 'Colette Browning', 58302: 'Skye Homsi', 48502: 'Hiroto Yamaguchi', 48291: 'Tobias Ledford', 48293: 'Jin Xu', 23945: 'Joana Dias', 85823: 'Alton Derosa'} # dict # Ask user for an ID, then display the name # If the ID is not in the dictionary, display the exception message try: # try user = int(input("Type in the Id:- ")) # stores user input in int form if user in records.keys(): # if user in the keys of records print("Employee Name:-", records[user]) # print this else: # else print("Key not found") # print this except Exception as exception_object: # except unexpected errors print(exception_object) # prints this instead except KeyError as exception_object: # excepts error print("Invalid Key") # prints this instead

# [ ] Use the `records` dictionary in a program to 1. ask the user for an ID then 2. delete the employee record associated with the ID # The program should display an appropriate message if the ID is not found in the dictionary. # hint: Try/Catch may be helpful here records = {57394: 'Suresh Datta', 48539: 'Colette Browning', 58302: 'Skye Homsi', 48502: 'Hiroto Yamaguchi', 48291: 'Tobias Ledford', 48293: 'Jin Xu', 23945: 'Joana Dias', 85823: 'Alton Derosa'} # ask user for an ID # if ID is not in the dictionary, the exception message will be displayed try: # try user = int(input("Type in the Id:- ")) # stores user input in int form if user in records.keys(): # if user in the keys of records print("Deleted Employee's Name:-", records[user]) # print this records.pop(user) print(records) else: # else print("Key not found") # print this except Exception as exception_object: # except unexpected errors print(exception_object) # prints this instead except KeyError as exception_object: # excepts error print("Invalid Key") # prints this instead

D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'} # dict # Iterate over the keys of D for key in D.keys(): # for all the keys in D print("D[{}] = '{}'".format(key, D[key])) # prints, formats

D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'} # dict # Iterate over the sorted keys of D # Keys sorted alphabetically because they are all strings for key in sorted(D.keys()): # for every key in D, which is sorted print("D[{}] = '{}'".format(key, D[key])) # prints, formats

D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'} # dict for value in D.values(): # for every value in D print(value) # prints

D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'} # dict for (key, value) in D.items(): # for every item in D print(key,':', value) # prints

D = {'Name':'Skye', 'Age':35, 'Temperature':98.7, 'Last Name': 'Babic'} # dict for key, value in D.items(): # for items in D print(key,':', value) # prints

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} # Display the price for the items in a sorted order for item in sorted(groceries.keys()): # for every key in groceries, which is sorted print("{} = {:.2f}".format(item, groceries[item])) # prints, formats

# [ ] The `data` list contains information about a company's employees # Use the `data` list and an appropriate loop to create a dictionary of # IDs (as keys): [name, email] (as values) # The resulting dictionary should look like: # {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']} data = [["Suresh Datta", 57394, "suresh@example.com"], ["Colette Browning", 48539, "colette@example.com"], ["Skye Homsi", 58302, "skye@example.com"], ["Hiroto Yamaguchi", 48502, "hiroto@example.com"], ["Tobias Ledford", 48291, "tobias@example.com", "Tamara Babic", 58201, "tamara@example.com"], ["Jin Xu", 48293, "jin@example.com"], ["Joana Dias", 23945, "joana@example.com"], ["Alton Derosa", 85823, "alton@example.com"]] # list for item in data: # for item in data print("{", item[1], ": [", item[0], ",", item[2], "]}") # prints # I have absolutely no idea how to do this. I tried my best

# [ ] Write a program to display the content of the `records` dictionary as shown here # Make sure to display the header the dictionary makes sense to the viewer # Note the IDs are sorted in an ascending order ''' Name | ID | Email ________________________________________________________ Joana Dias | 23945 | joana@example.com Tobias Ledford | 48291 | tobias@example.com Jin Xu | 48293 | jin@example.com Hiroto Yamaguchi | 48502 | hiroto@example.com Colette Browning | 48539 | colette@example.com Suresh Datta | 57394 | suresh@example.com Skye Homsi | 58302 | skye@example.com Alton Derosa | 85823 | alton@example.com ''' records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']} # dict # Display the header print("| Name | ID | Email |") # prints for key, value in sorted(records.items()): # for items in the sorted dict print(" {} {} {}".format(value[0], key, value[1])) # prints, formats # I tried

# [ ] The company's domain has changed from (example.com) to (example.org) # Write a program to modify the email addresses in the `records` dictionary to reflect this change records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']} # dict # Display the updated dictionary # Display the header # Display the data (sorted by ID) address1 = "org" # stores address2 = "com" # stores records[address2] = address1 # replaces print(records) # prints # I genuinely have no idea why this is not working. I had to refer to the # notes section. Even then, it's not working.

# [ ] You want to send a mass email to all company employees, so you need a list of all the email addresses in `records` # Write a program to extract the email addresses from the `records` dictionary and store them in a list # The output list should look like: # ['suresh@example.com', 'colette@example.com', 'skye@example.com', 'hiroto@example.com', 'tobias@example.com', 'jin@example.com', 'joana@example.com', 'alton@example.com'] # Hint: use the `.values()` method records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']} # dict for email in records.values(): # for email in the values of records print("['" + email[1] + "'], ", end = " ") # prints # I failed to do the shell ( "[]" ).

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} # dict item = input("Please enter an item name: ") # stores user input # Using .keys() if (item in groceries.keys()): # if item is in the keys of groceries print("Price of {} is: ${:4.2f}".format(item, groceries[item])) # prints, formats elif (item not in groceries): # else if the item is not in groceries print("Price not in the dictionary") # prints

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} # dict item = input("Please enter a item: ") # stores user input # Without using .keys() if (item in groceries): # if item is in groceries print("Price of {} is: ${:4.2f}".format(item, groceries[item])) # prints, formats elif (item not in groceries): # else if item is not in groceries print("Price not in the dictionary") # prints

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} # dict price = float(input("Please enter an exact price: ")) # stores in float form if (price in groceries.values()): # if price is in the values of groceries print("There is a matching grocery") # prints else: # else print("There are no groceries matching this price") # prints

# Create 2 equal but not identical dictionaries D1 = {0:'number 0', 1:'number 1', 2:'number 2'} D2 = {1:'number 1', 0:'number 0', 2:'number 2'} # dict print("Equality: D1 == D2 ?", D1 == D2) # D1 equals D2 = Yes print("Identity: D1 is D2 ?", D1 is D2) # D1 is D2 = No

# Create 2 equal and identical dictionaries D1 = {0:'number 0', 1:'number 1', 2:'number 2'} # dict D2 = D1 # D1 is now D2 D1[0] = 'changed number' # replaces index 0 of D1 print("Equality: D1 == D2 ?", D1 == D2) # D1 equals D2 = Yes print("Identity: D1 is D2 ?", D1 is D2) # D1 is D2 = No print("D2 after changing D1:", D2) # prints

# Create a dictionary of grocery items and associated prices groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} # dict # The length of a dictionary = how many key:value pairs it has print("{} groceries total".format(len(groceries))) # prints, formats

# Write a program that can ONLY update the PRICE of an existing grocery item in the `groceries` dictionary. # The item and updated price should be entered by the user. # If the user enters a new item, the program should NOT create a new dictionary item. # It should instead display an error message. groceries = {'Bread':2.26, 'Milk':3.62, 'Chocolate':1.59} # dict item = input("Type In The Item:- ") # stores user input price = float(input("Type In The Price:- ")) # stores user input in float form if item not in groceries: # if item is not in groceries print("Error: Item Not Found") # print this else: # else groceries[item] = price # the item (key) in groceries will not equal to the price (value) print(groceries) # print this

# [ ] Write a program to find out the number of employees stored in `records`. records = {57394: ['Suresh Datta', 'suresh@example.com'], 48539: ['Colette Browning', 'colette@example.com'], 58302: ['Skye Homsi', 'skye@example.com'], 48502: ['Hiroto Yamaguchi', 'hiroto@example.com'], 48291: ['Tobias Ledford', 'tobias@example.com'], 48293: ['Jin Xu', 'jin@example.com'], 23945: ['Joana Dias', 'joana@example.com'], 85823: ['Alton Derosa', 'alton@example.com']} # dict print(len(records)) # prints length of records