# Noemi Cabrera # 19 November 2021 # In this lesson, I learned how to create timedelta objects using the timedelta() function, use # timedelta objects to perform date arithmetic (*, /, //, -, +), compare two datetime objects # using comparison operators, and build a useful application using timedelta arithmetic like finding # the time until a certain date happens. Additionally, you can calculate the total number of # seconds in a date by using the total_seconds() function. To summarize, the timedelta function # allows you to perform arithmic operations with dates. # I didn't have any major difficulties in this lesson.

# In this code, the timedelta function is imported from the datetime module. Then this function is used to display # the delta time that it's specified with days, seconds, minutes, hours, and weeks. The the days, seconds, and # microseconds attributes are accessed by writing them after the 'delta1' variable, which contains the delta time. # These values are displayed. Then, the total seconds of the entire delta time are calculated by using the # total_seconds() method. from datetime import timedelta # Define a timedelta object delta1 = timedelta(days = 2, seconds = 0, minutes = 15, hours = 1, weeks = 4) print(delta1, " is stored in delta1") # Get the stored attributes d = delta1.days s = delta1.seconds ms = delta1.microseconds print("Days = ", d, "| Seconds = ", s, "| Microseconds = ", ms) # Get total number of seconds all_seconds = delta1.total_seconds() print("Total number of seconds = ", all_seconds)

# In this code, the timedelta and datetime functions are imported from the datetime module. Then, datetime is used to get # a date, which is stored in 'date1', and the current date by using today(), which is stored in 'date2'. # With the timedelta function vailable, date1 can substracted from date2 and the result is stored in the delta2 variable. # Lastly, the total seconds of the date are calculated by using the total_seconds() function and then displayed. from datetime import datetime, timedelta date1 = datetime(year = 2015, month = 1, day = 19) date2 = datetime.today() # Define a time delta delta2 = date2 - date1 print(delta2, " is stored in delta2") print("Total number of seconds = ", delta2.total_seconds())

# In this code, the timedelta function is imported from the datetime module. Then this function is used to display # the delta time that it's specified with minutes, hours, and weeks. # [ ] Create a `timedelta` object that contains: 2 hours, 3 minutes, and 1 week from datetime import timedelta delta_o = timedelta(minutes = 3, hours = 2, weeks = 1) print(delta_o)

# In this code, the timedelta function is imported from the datetime module. Then this function is used to get # the delta time that it's specified with minutes and hours. Then, the total seconds of the entire delta time # are calculated by using the total_seconds() method. This is stored in the 't_secs' variable displayed using # print(). # [ ] Use a `timedelta` object to calculate the total number of seconds in: 1 hour and 15 minutes from datetime import timedelta delta2_o = timedelta(minutes = 15, hours = 1) t_secs = delta2_o.total_seconds() print("Total number of seconds:",t_secs)

# In this code, the timedelta and date functions are imported from the datetime module. Then, date is used to get # the date of my next birthday, which is stored in 'bd', and the current date, which is stored in 'cd'. # With the timedelta function available, 'cd' is substracted from 'bd' and the result is stored in the 'd_left' variable. # Lastly, the total days until my next birthday are displayed because '.days' is used besides the 'd_left' variable # in the print statement. # Use a `timedelta` object to find out how many days are left until your upcoming birthday from datetime import timedelta, date bd = date(month = 6, day= 24, year= 2022) print("My next birthday is on:",bd) cd = date.today() d_left = bd - cd print(d_left.days, "days are left until my next birthday")

# In this code, the timedelta and datetime functions are imported from the datetime module. Then, timedelta is used to get # a date with only 100 days specified. The current date is get by using the datetime function with .today(). # In the 'new_date' variable, the 100 days are added to the current date. Lastly, the new date is printed in string # format using the strftime() function. from datetime import datetime, timedelta # Define a timedelta object one_hundred_days = timedelta(days = 100) # Get today's date current_date = datetime.today() # Compute the new date new_date = current_date + one_hundred_days # Print formatted new date print("After 100 days:", new_date.strftime("%b/%d/%Y"))

# In this code, the timedelta and datetime functions are imported from the datetime module. Then, timedelta is used to get # a date with only 100 days specified and this is stored in the one_hundred_days. To get 200 & 300 days, the 'one_hundred_days' # is multiplied by 2 and 3. The current date is get by using the datetime function with .today(). # In the 'new_date1' variable, the 200 days are added to the current date. In the 'new_date2' variable, the 300 days are added # to the current date. Lastly, the new dates are printed in string format using the strftime() function. from datetime import datetime, timedelta # Define the timedelta objects one_hundred_days = timedelta(days = 100) two_hundred_days = one_hundred_days * 2 three_hundred_days = one_hundred_days * 3 # Get today's date current_date = datetime.today() # Compute the new dates new_date1 = current_date + two_hundred_days new_date2 = current_date + three_hundred_days # Print formatted new dates print("After 200 days:", new_date1.strftime("%b/%d/%Y")) print("After 300 days:", new_date2.strftime("%b/%d/%Y"))

# In this code, the timedelta and date functions are imported from the datetime module. In the three_w variable, # timedelta is used to get a date with only 3 weeks specified. My birthday date is get by using the date function # and then stored in the 'bd' variable. In the 'date_three_w' variable, the 3 weeks are substracted from my # birthday date. Lastly, the new date is printed in string format using the strftime() function. # [ ] Write a program to compute the date 3 weeks before your birthday # to help you remember when to send the invitations from datetime import date, timedelta three_w = timedelta(weeks = 3) # Get today's date bd = date(month= 6, day= 24, year = 2022) print('My birthday:',bd) # Compute the new date date_three_w = bd - three_w # Print formatted new date print("Date 3 weeks before my birthday :", date_three_w.strftime("%b/%d/%Y"))

# In this code, the timedelta and date functions are imported from the datetime module. The current date is # accessed by using the date function and .today(). Then, the current date is substracted from my birthday # date and this is stored in the td1 variable. The id2 variable is assigned the delta time of # 3 weeks. Lastly, in the 'td' variable, td2 is substracted from the td1 to get the date from the current date till # the 3 weeks reminder for my birthday. The number of days from the current date till the 3 weeks reminder # is displayed by using .days after 'td'. # [ ] Write a program that computes the number of days from the current date till the 3 weeks reminder # 1) Create a `timedelta` object (td1) for the period between the current date and your upcoming birthday # 2) Create a `timedelta` object (td2) containing 3 weeks # 3) Use the `timedelta` objects (td) from 1 and 2 to compute the required number of days from datetime import date, timedelta c_date = date.today() td1 = bd - c_date td2 = timedelta(weeks = 3) td = td1 - td2 print("Number of days from the current date till the 3 weeks reminder of my birthday :", td.days)

# In this code, the date function is imported from the datetime module. This function is used to # get two birthday dates. In the if/else statement it's determined which person is older based # on the birthdays previously defined. The < and > operators are used to compare the dates. # So, if birthday1 is greater than birthday2, then person with birthday1 is older. If birthday1 # is less than birthday2, then person with birthday2 is older. Else, they have the same age. from datetime import date # Birthday of person 1 birthday1 = date(year = 1993, month = 3, day = 5) # Birthday of person 2 birthday2 = date(year = 2003, month = 3, day = 20) # Compare birthdays if (birthday1 > birthday2): print("Person 2 is older") elif (birthday1 < birthday2): print("Person 1 is older") else: print("Person 1 and Person 2 are of the same age")

# In this code, the date function is imported from the datetime module. This function is used to # get the date for 4th of July of 2021. The current date is accessed by using date and .today(). # In the if/else statement it's if 4th of July of this year has passed or not. # So, if current date is greater than the 4th of July date, then 4th of July has already passed. # But if current date is not greater than the 4th of July date, , then 4th of July has already passed. # [ ] Write a program to find out if 4th of July of this year has passed or not from datetime import date c_july_4th = date(year =2021, month = 7, day = 4) c_date = date.today() if (c_date > c_july_4th): print("4th of July of this year has passed") else: print("4th of July of this year has not passed")

# In this code, the datetime function is imported from the datetime module. The current date is # accessed by using the datetime function and '.today()'. The date for december solstice is stored # in the 'solstice' variable. The year of the solstice is replace with the year of teh current date # defined at the beginning. Then, the current date is substracted from the december solstice # date and this is stored in the 'count' variable. The number of days from the current date # till december solstice is displayed by using .days after 'count'. from datetime import datetime # Define today's date now = datetime.today() # December solstice of year 1, it can be any year, it will be changed later solstice = datetime(month = 12, day = 21, year = 1) # Change solstice's year to current year solstice = solstice.replace(year = (datetime.today().year)) # Get the timedelta count = solstice - now # Display the solstice countdown print("There are", count.days, "days until the December solstice!" )

# In this code, the datetime function is imported from the datetime module. The current date is # accessed by using the datetime function and '.today()'. The date for december solstice is stored # in the 'december_solstice' variable. The date for july solstice is stored in the 'july_solstice' # variable. Then, the current date is substracted from both the december solstice and july sostice # to find out later for which solstice the time to wait is less. If the count for december solstice # is greater than the count for july solstice, december is not closer to the current date. If it's # not greater, then december solstice is closer to the # current date. # [ ] Complete the following program to find out if you are closer to the current year's June or December solstice # Define today's date now = datetime.today() # Define the December solstice december_solstice = datetime(month = 12, day = 21, year = now.year) # Define the June solstice june_solstice = datetime(month = 6, day = 21, year = now.year) # Find out which solstice is closer #TODO count_ds = now - december_solstice count_js = now - june_solstice if (count_ds > count_js): print("I am are closer to the current year's June solstice") else: print("I am are closer to the current year's December solstice")