# Noemi Cabrera # 25 October 2021 # In this lesson, I learned to use the len(), .count(), and .find() methods. These can # be used in combination with loops, if/else staments, etc. # len() returns the number of characters of a string. # .count() returns the number of times a certain letter, word, or phrase appears in # a string. # .find() returns the index conut of the 1st character in a string. # The difficulties I had were with the last Task where I had to create a program that # printed each word of a string in a new line. To fix this, I added an else statement that # included the last word of the string and printed the statement quote[start:space_index].

# [ In this code, the functions len(), .count, and .find() are used only using the # variable work_tip. The lenght of characters of the string found the variable work # tip is displayed by using len(). Using .count(), the # of times the letter e appears # is displayed. Lastly, using the unction .find(), the index of a certain letter is # found and displayed. String slicing is used to indicate from which indexes the # letter has to be fonud in.] review and run example work_tip = "save your code" print("number of characters in string") print(len(work_tip),"\n") print('letter "e" occurrences') print(work_tip.count("e"),"\n") print("find the index of the first space") print(work_tip.find(" "),"\n") print('find the index of "u" searching a slice work_tip[3:9] -', work_tip[3:9]) print(work_tip.find("u",3,9),"\n") print('find the index of "e" searching a slice work_tip[4:] -', work_tip[4:]) print(work_tip.find("e",4))

# [ In this code, the len() function is used to display the lenght or # of characters # of the string "good code is commented."The lenght is added to strings by using a comma.] # review and run example work_tip = "good code is commented code" print("The sentence: \"" + work_tip + "\" has character length = ", len(work_tip) )

# [ In this code, the lenght of the string "good code is commented code" is divided in # half . Then, using string sicling, the 1st half o fthe string is printed and the 2nd # half of the string is printed in separate lines. ] review and run example # find the middle index work_tip = "good code is commented code" mid_pt = int(len(work_tip)/2) # print 1st half of sentence print(work_tip[:mid_pt]) # print the 2nd half of sentence print(work_tip[mid_pt:])

# [ In this code, the function .count() is used. It counts how many times "w", "o", # and "code" is found in the variable work_tip. The value is displayed.] # review and run example print(work_tip) print("how many w's? ", work_tip.count("w")) print("how many o's? ", work_tip.count("o")) print("uses 'code', how many times? ", work_tip.count("code"))

# [In this code, the .count() function is used along with string slicing. Here, the # previous variables word_tip & mid_pt are used. The letter o is searched in the first # and second half of the string "good code is commented" located in word_tip.] # review and run example print(work_tip[:mid_pt]) print("# o's in first half") print(work_tip[:mid_pt].count("o")) print() print(work_tip[mid_pt:]) print("# o's in second half") print(work_tip[mid_pt:].count("o"))

# [ In this code, the function .find is used, which displays the index count of the 1st # character of a string. In this case, it displays the starting index count of the # substring "code" found in the variable work_tip.] review and run example work_tip = "good code has meaningful variable names" print(work_tip) # index where first instance of "code" starts code_here = work_tip.find("code") print(code_here, '= starting index for "code"')

# [ In the .find() function, you can also set the start and end index in which you # want to find the index count of the 1st character. In this case, the index count # of the word meaning is searched from index 13 up to index 33. ] review and run example # set start index = 13 and end index = 33 print('search for "meaning" in the sub-string:', work_tip[13:33],"\n") meaning_here = work_tip.find("meaning",13,33) print('"meaning" found in work_tip[13:33] sub-string search at index', meaning_here)

# [ In this code, the function .find() is used along with a while loop. WHile "o" is # found in the word_tip variable, the index on which it appears will display until no # more o's are found in word_tip (the .find() function returns -1 if no o's are found # and the loop ends.).] review and run example # if .find("o") has No Match, -1 is returned print ("work_tip:" , work_tip) location = work_tip.find("o") # keeps looping until location = -1 (no "o" found) while location >= 0: print("'o' at index =", location) # find("o", location + 1) looks for a "o" after index the first "o" was found location = work_tip.find("o", location + 1) print("no more o's")

# [ In this code, I divided the lenght of random_tip by 2 to find its midpoint, the # variable who contains this is called mid_random. ] use len() to find the midpoint of # the string #[I printed 1st and 2nd half of random_tip by using string slicing] print the halves # on separate lines random_tip = "wear a hat when it rains" mid_random = int(len(random_tip)/2) print(random_tip[:mid_random]) print(random_tip[mid_random:])

# for letters: "e" and "a" in random_tip # [ I used the function .count() to find how many times the letter e and a appear # in random_tip. ] print letter counts # [ I used an if/else statement to display which letter appeared the most in random_tip.] # BONUS: print which letter is most frequent random_tip = "wear a hat when it rains" print("\'e\'appears",random_tip.count('e'),'times') print("\'a\'appears",random_tip.count('a'),'times') print() if random_tip.count('e') > random_tip.count('a'): print("\'e\' appears the most in random_tip") else: print("\'a\' appears the most in random_tip")

# [ ] print long_word from the location of the first and second "t" long_word = "juxtaposition" first_t = long_word.find("t",0,4) second_t = long_word.find("t",4,-1) print(long_word[first_t:9]) print(long_word[second_t:])

quote = "they stumble who run fast" start = 0 space_index = quote.find(" ") while space_index != -1: print(quote[start:space_index]) start = space_index + 1 space_index = quote.find(" ", space_index + 1) else: print (quote[start::1])